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The function: Complete and Solve!

 Apr 17, 2019
 #1
avatar+6046 
+1

what do you need help with?

 Apr 17, 2019
 #2
avatar+7763 
+2

A "strange" thing to say is that, year 2000 is 0 years after year 2000.

So we substitute t = 0, and we get:

Population living in the city in 2000 = \(2e^{0.06(0)} = 2(1) =2\text{ millions}\)

 Apr 18, 2019
edited by MaxWong  Apr 18, 2019
 #3
avatar+7763 
+1

Obviously, the growth is an exponential growth, as the modelling function suggests.

 Apr 18, 2019
 #4
avatar+7763 
+1

Year 2019 is 19 years after Year 2000.

The current population is \(2e^{0.06(19)} \approx 6.253537 \text{ millions}\)

Approximately 6,253,537 people live in this city.

 Apr 18, 2019

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