#1**+5 **

OK....this seems a little confusing....but it's not too bad....

First, we need to see that x= √2 ≤ pi.....so this tells us that we should use the first piecewise function to evaluate h(√2)..so we have

h(√2) = floor (4√2) = 5

Now.....we want to put this result back into h(x)...but note....now we must use the piecewise function 3 - x since the "x" we're putting into h lies* between* pi and 5.2

So we have

f(5) = 3 - 5 = -2

So h(h(√2)) just evaluates to -2

CPhill Jan 8, 2015

#1**+5 **

Best Answer

OK....this seems a little confusing....but it's not too bad....

First, we need to see that x= √2 ≤ pi.....so this tells us that we should use the first piecewise function to evaluate h(√2)..so we have

h(√2) = floor (4√2) = 5

Now.....we want to put this result back into h(x)...but note....now we must use the piecewise function 3 - x since the "x" we're putting into h lies* between* pi and 5.2

So we have

f(5) = 3 - 5 = -2

So h(h(√2)) just evaluates to -2

CPhill Jan 8, 2015