The function \(f(n) = 3f(n-2) - 2f(n-1)\), where \(f(2) = 3\) and \(f(1) = -1\) . What is the value of \(f(5)\)?
I cant find the edit botton so ..
The function \(f(n) = 3f(n-2) - 2f(n-1) \) , where \(f(2) = 3\) and \(f(1) = -1\) . What is the value of \(f(5)\) ?
Is this any better ?
Tell me if not.
f(5) = 3f(5-2) - 2f(5 - 1)
f(5) = 3f(3) - 2f(4)
f(5) = 3 [ 3f(3-2) - 2f(3 - 1) ] - 2 [ 3f(4-2) -2f(4 - 1)]
f(5) = 3 [ 3f(1) - 2f(2)] - 2[ 3f(2) - 2f(3) ]
f(5) = 3 [ 3(-1) - 2(3) ] - 2 [ 3(3) - 2f(3) ]
f(5) = 3[ -9] - 2 [ 9 ] + 4f(3)
f(5) = -45 + 4 [3f(3 - 2) - 2f(3 - 1)]
f(5) = -45 + 4 [ 3f(1) - 2f(2) ]
f(5) = -45 + 4 [ 3(-1) - 2(3) ]
f(5) = -45 +4 [ -3 - 6 ]
f(5) = -45 + 4 (-9)
f(5) = -45 - 36
f(5) = -81