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The function \(f(n) = 3f(n-2) - 2f(n-1)\), where \(f(2) = 3\) and \(f(1) = -1\) . What is the value of \(f(5)\)?

 Oct 28, 2019
 #1
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please help.ive been stuck on this for nearly 1 hr 

 Oct 29, 2019
 #2
avatar+656 
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i'd try to help but i am sort of confused in a way :( 

could you write the functions more spaces out please and i'll try to help! :) 

thank you >w<

 Oct 29, 2019
edited by Nirvana  Oct 29, 2019
 #3
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+1

I cant find the edit botton so ..

 

The function  \(f(n) = 3f(n-2) - 2f(n-1) \)  , where  \(f(2) = 3\)  and   \(f(1) = -1\)  . What is the value of   \(f(5)\) ?

 

Is this any better ?

Tell me if not.

 Oct 29, 2019
 #5
avatar+656 
+1

oh my god im so sorry i just saw this :( 

but it seems like CPhill already worked it out and tried to help you!! but if you still have questions i can help :D 

sooooo thanks to CPhill!! cool

Nirvana  Oct 29, 2019
 #4
avatar+104933 
+2

f(5)  =  3f(5-2) - 2f(5 - 1)

f(5)  = 3f(3) - 2f(4)

 

f(5)  = 3 [ 3f(3-2) - 2f(3 - 1) ] - 2 [ 3f(4-2) -2f(4 - 1)]

f(5)  = 3 [ 3f(1) - 2f(2)] - 2[ 3f(2) - 2f(3) ]

f(5)  =  3 [ 3(-1) - 2(3) ]  - 2 [ 3(3) - 2f(3) ]

f(5) = 3[ -9] - 2 [ 9 ] + 4f(3)

f(5) = -45 + 4 [3f(3 - 2) - 2f(3 - 1)]

f(5) = -45 + 4 [ 3f(1) - 2f(2) ] 

f(5)  = -45 + 4 [ 3(-1) - 2(3) ]

f(5)  = -45 +4 [ -3 - 6 ]

f(5)  = -45 + 4 (-9)

f(5)  = -45 - 36

f(5)  = -81

 

 

cool cool cool

 Oct 29, 2019

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