The graph above is the graph of y=x2 translated and reflected in the xy-plane. Find an equation for this graph.
Please help
y = x^2 has the vertex at (0, 0)
So....we have
y = (x - 0)^2 + 0
This graph translates the vertex to the left 7 units and up 4 units
So...we have
y = ( x + 0 + 7) ^2 + ( 0 + 4 )
y = ( x + 7)^2 + 4
Thanks for the answer! I have a question though. Shifting it to the left makes it -7, so how does it turn positive?
This is always confusing....
Note that we have
(x + 7)^2 + 4
The form that we are really going for is
( x - h)^2 + k where ( h, k) is the vertex
So....
(x - (-7) )^2 + 4 produces the vertex (h, k) = (-7, 4)
But this is just the same as
(x + 7)^2 + 4
Remember that a " + " moves the x coordinate of the vertex to the left and a " - " moves the x coordinate of the vertex to the right
To get a feel for this....look at the graph here : https://www.desmos.com/calculator/4ryl8slhym
y = ( x + 2)^2 shifts the vertex of y = x^2 to the left 2 units
y = ( x - 2)^2 shifts the vertex of y = x^2 to the right by 2 units