+0  
 
0
167
1
avatar+203 

The graph of y=ax^2+bx+c is given below, where a, b, and c are integers. Find a-b+c.
 

 Mar 20, 2021
 #1
avatar+121000 
+1

The  vertex  is at  (-1, -2)

 

We have the form

 

y = a ( x - - 1)^2  - 2

 

y =  a ( x + 1)^2  - 2

 

And  the point  0,-1)  is on the graph...so we  can find a

 

-1  = a ( 0 + 1)^2  - 2

 

-1 + 2  =  a

 

1 = a

 

So  we havr

 

y = 1 ( x + 1)^2  -  2

 

y = x^2  + 2x  + 1  - 2

 

y = x^2  + 2x  - 1

 

a = 1   b = 2    c = -1

 

a + b + c =  1 + 2  - 1    =  2

 

cool cool cool

 Mar 20, 2021

25 Online Users

avatar
avatar
avatar