+109 The half-life of carbon-14 is 5,730 years. Assuming you start with 100% of carbon-14, what is the expression for the percent, P(t), of carbon-14 that remains in an organism that is t years old and what is the percent of carbon-14 remaining (rounded to the nearest whole percent) in an organism estimated to be 12,000 years old?
Hint: The exponential equation for half-life is P(t) = A0(0.5)t/H, where P(t) is the percent of carbon-14 remaining, A0is the initial amount (100%), t is age of the organism in years, and H is the half-life
A.) P(T)=100(0.5)^5,730t, 23% remaining
B.) P(t)=100(0.5)^t/5730, 23% remaining
C.) p(t)=5,730(0.5)^100/t, 5690 remaining
D.) p(t)=100 (0.5)^5,730/t, 77% remaining
