The height of a cylindrical can is 2.25 inches greater than the measure of the can’s diameter. The volume of the cylinder is 52.18 in^3. What are the can’s dimensions? Use 3.14 for pi.

RainbowPanda Dec 6, 2018

#1**+2 **

Volume of a cylinder = pi r^2 h

h = 2r+2.25 (given) and V = 52.18 in^3 (given)

Substitute

52.18 = (3.14) (r^2)(2r+2.25) expand

52.18 = (3.14) (2r^3 + 2.25 r^2) divide by 3.14

16.617834 = 2r^3 + 2.25r^2 re-rrange

2r^3 +2.25r^2 - 16.617834 = 0 Solving GRAPHICALLY r = 1.7115 in

So the cylinder is d = (1.7115 x 2 ) = 3.423 in & h= 2.25 + d = 5.673 in

ElectricPavlov Dec 6, 2018