1. The hypotenuse of an isosceles right triangle is 14sqrt(2). How long is each leg of the triangle?

2. The hypotenuse of an isosceles right triangle is 14sqrt(2). What is the area of the triangle?

weredumbmaster22 Mar 23, 2021

#1**+3 **

Both questions use the same triangle:

Note that an isosceles right triangle is a 1-1-sqrt(2) triangle;

meaning that we can find the legs by dividing the hypotenuse by sqrt(2).

\(14{\sqrt {2}}{\div }{\sqrt {2}}=14\)

1. The leg of the triangle is **14 units long**.

The area is simply bh/2, where b=14 and h=14.

\({\frac {bh} {2}}={\frac {14{\times }14} {2}}=98\)

2. The area of the triangle is **98 square units**.

ArithmeticBrains1234 Mar 23, 2021