The length of a swimming pool is 20 feet greater than its width. The area of the pool is 525 square feet.
+128407 Let the width = W
And the length is 20 more = W + 20
And area = W x L, so we have
W x (W + 20) = 525
W^2 + 20W = 525 subtract 525 from each side
W^2 + 20W - 525 = 0 factor
(W - 15) (W + 35) = 0 and setting each factor to 0, we have that W = -35 or W = 15
Reject -35
So W = 15 .....and the length is 20 more = 35
+128407 Let the width = W
And the length is 20 more = W + 20
And area = W x L, so we have
W x (W + 20) = 525
W^2 + 20W = 525 subtract 525 from each side
W^2 + 20W - 525 = 0 factor
(W - 15) (W + 35) = 0 and setting each factor to 0, we have that W = -35 or W = 15
Reject -35
So W = 15 .....and the length is 20 more = 35
