The line $x = k$ intersects the graph of the parabola $x = -2y^2 - 3y + 5$ at exactly one point. What is $k$?

Guest Jun 21, 2022

#1**+1 **

The line \(x = k \) can only intersect the parabola at the vertex.

The y-coordinate of the vertex is \(-{b \over 2a} = {-3 \over 4}\)

Substituting this in for y gives us: \(x = -2(-0.75)^2 - 3(-0.75) + 5\), meaning \(k = \color{brown}\boxed{6 {1 \over 8}}\)

BuilderBoi Jun 21, 2022