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The Mathletes won 2 of their first 10 meets. They went on to win all their remaining meets and finished the year with an equal number of wins and losses. What is the total number of meets in which the Mathletes competed?

 Jun 28, 2015

Best Answer 

 #1
avatar+427 
+5

I hope I understood the question correctly:

We have 2 wins, and 8 loses. They then win x amount more and end on equal loses and wins

So:

2 + x = 8

x = 6

 

10 meets + 6 = 16 total meets.

 Jun 28, 2015
 #1
avatar+427 
+5
Best Answer

I hope I understood the question correctly:

We have 2 wins, and 8 loses. They then win x amount more and end on equal loses and wins

So:

2 + x = 8

x = 6

 

10 meets + 6 = 16 total meets.

Sir-Emo-Chappington Jun 28, 2015

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