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The probability of choosing two green balls without replacement is 1150 ,  and the probability of choosing one green ball is1225 .

What is the probability of drawing a second green ball, given that the first ball is green?

 

Answer choices:

  • 7/10
  • 11/12
  • 66/625
  • 11/24
 Feb 4, 2018
 #2
avatar+101369 
+3

12/25  (     )   =  11/50

 

(     )   =    11/50 * 25/12    =   275 / 600   =   

 

11/24

 

This can also be found by "formula"

 

Let A  =  Prob of second ball green

B  = First ball is green  =  12/25

P (A and B)  =  P (Both balls are green)  =  11/50

 

P ( A  given B )   =   P( A and B)  / P (B) 

 

So we have  :

 

P ( A given B)  =   ( 11/50) / (12/25)   =   (11/50) (25/12)  =  11/24

 

 

cool cool cool

 Feb 5, 2018

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