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The probability that a student owns a dog is 1/3. The probability that the same student owns a dog and the cat is 2/15. Determine the probability that the student owns a cat

Guest Jun 3, 2015

Best Answer 

 #1
avatar+93691 
+10

Assuming that the events are independent then

 

$$\\\frac{1}{3}\times P(Cat)=\frac{2}{15}\\\\
P(Cat)=\frac{2}{15}\div \frac{1}{3} \\\\
P(Cat)=\frac{2}{15}\times \frac{3}{1} \\\\
P(Cat)=\frac{2}{\not{15}^5}\times \frac{\not{3}^1}{1} \\\\
P(Cat)=\frac{2}{5} \\\\$$

Melody  Jun 3, 2015
 #1
avatar+93691 
+10
Best Answer

Assuming that the events are independent then

 

$$\\\frac{1}{3}\times P(Cat)=\frac{2}{15}\\\\
P(Cat)=\frac{2}{15}\div \frac{1}{3} \\\\
P(Cat)=\frac{2}{15}\times \frac{3}{1} \\\\
P(Cat)=\frac{2}{\not{15}^5}\times \frac{\not{3}^1}{1} \\\\
P(Cat)=\frac{2}{5} \\\\$$

Melody  Jun 3, 2015

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