The product of two consecutive odd integers is 99. Find the integers. Show work. Correct answer with very little work will receive no credit.

 Nov 29, 2021

We can first set the smaller one to be \(a\), and the larger one to be \(a+2\). Now, the problem tells us that \(a(a+2)=99\). Multiplying out and rearranging, we obtain the equation \(a^2+2a-99=0\). We can factor this as \((a-9)(a+11)=0\), so the solutions are \(a=-11\) or \(a=9\). This means that the odd integers could either be \(\boxed{-11,-9}\), or they could be \(\boxed{9,11}\).


Hope this helped laugh

 Nov 29, 2021

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