The roots of y^2 + 5y - 11 = 0 are a and b. Find (a + 3)(b + 3).
The roots a and b are −5±√693
so (a + 3)(b + 3) = (−5+√693+3)(−5−√693+3)=−21
Adding onto Guest's answer:
You use the quadratic formula to find the roots of y^2+5y-11.
The quadratic formula is:
-b+-sqrt(b^2-4ac) / 2a
So, in this case, a=1, b=5, and c=-11