+394 The shaded area of the figure may be found by subtracting the area of the unshaded portion from the total area of the figure. Use this approach to find the area of the shaded region. Use 3.14 as an approximation for
piπ. A circle with a diameter of 38 meters is inscribed inside a square.38 m (a circle within a square)
The area of the shaded region is approximately _______
m cubed .m3.
m squared .m2.
m.m.
(Simplify your answer. Round to the nearest hundredth as needed.)
+9481 Notice that the side length of the square is 38 m.
area of square = (side length)2 = (38 m)2 = 1444 m2
Notice that the diameter of the circle is 38 m .
And its radius = diameter / 2 = 38m / 2 = 19 m
area of circle = pi * radius2 = pi * (19m)2 = pi * 361 m2 ≈ 1133.54 m2
So......
area of shaded region = area of square - area of circle
area of shaded region ≈ 1444 m2 - 1133.54 m2
area of shaded region ≈ 310.46 m2
+9481 Notice that the side length of the square is 38 m.
area of square = (side length)2 = (38 m)2 = 1444 m2
Notice that the diameter of the circle is 38 m .
And its radius = diameter / 2 = 38m / 2 = 19 m
area of circle = pi * radius2 = pi * (19m)2 = pi * 361 m2 ≈ 1133.54 m2
So......
area of shaded region = area of square - area of circle
area of shaded region ≈ 1444 m2 - 1133.54 m2
area of shaded region ≈ 310.46 m2
