The solution set of the equation: (x2 + 3) (x2 +1) = 0 where X belongs R is.....? asap pls

(x^2 + 3) (x^2 + 1)   = 0

There are no real number solutons to this......

Setting  both factors to 0   we have

x^2 + 3  = 0                    x^2 + 1 =  0

x^2  =  -3                       x^2 = -1

Note that any real number squared is either 0 or positive

So....no real numbers exist that make either equation true