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The square with vertices $(-1, -1)$, $(1, -1)$, $(-1, 1)$ and $(1, 1)$ is cut by the line $y=\frac{x}{2}+ 1$ into a triangle and a pentagon.

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The square with vertices $(-1, -1)$, $(1, -1)$, $(-1, 1)$ and $(1, 1)$ is cut by the line $y=\frac{x}{2}+ 1$ into a triangle and a pentagon. What is the number of square units in the area of the pentagon? Express your answer as a decimal to the nearest hundredth.

michaelcai  Oct 31, 2017
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#1
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The area of the triangle formed is

(1/2) [ 1/2 ] * [1]  =  1/4  units^2

The area of the square is  2 unirs on each side  =    2^2  =   4 units"2

So....the area of the pentagon is

4 - 1/4 =

4 - .25  =

3.75 units^2

CPhill  Oct 31, 2017

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