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The square with vertices $(-1, -1)$, $(1, -1)$, $(-1, 1)$ and $(1, 1)$ is cut by the line $y=\frac{x}{2}+ 1$ into a triangle and a pentagon. What is the number of square units in the area of the pentagon? Express your answer as a decimal to the nearest hundredth.

 Oct 31, 2017
 #1
avatar+128406 
+2

 

The area of the triangle formed is

 

(1/2) [ 1/2 ] * [1]  =  1/4  units^2

 

The area of the square is  2 unirs on each side  =    2^2  =   4 units"2

 

So....the area of the pentagon is

 

4 - 1/4 = 

 

4 - .25  = 

 

3.75 units^2

 

 

cool cool cool

 Oct 31, 2017

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