The two bases of a right conical frustum have radii 12 and 9. The two bases are 6 units apart. Let the volume of the frustum be V cubic units and the total surface area of the frustum be A square units. Find V + A.
I'll let you fill in the details
H= distance separating bases
R1 = 12
R2 = 9
V = (pi/3) * H * [ (R1)^2 + R1* R2 + (R2)^2 ]
A = pi [ ( R1 + R2) √ [ (R1 - R2)^2 + H^2 ] + (R1)^2 + (R2)^2 ]
