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The two diagonals of quadrilateral ABCD intersect at E. We know DC=12,CA=21,AB=18,BD=19, and Angle ABD=angle ACD. Find [BEC]/[AED].

 

                                                                                              

 

 

 

 

                                                                                                   

I don't know where to start for this problem and it won't let me look at the solution.

 Dec 29, 2021
edited by fuhsah  Dec 29, 2021
 #1
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What do the square brackets mean?

 Dec 29, 2021
 #2
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+1

area of the shape.

fuhsah  Dec 30, 2021
 #3
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Triangles ABE and CDE are similar.

 Dec 30, 2021
 #4
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+3

This is very simple. laugh

ΔABE ~ ΔCDE

BE = x         CE = y

x/18 = y/12

12x = 18y

y = 12x / 18

18 / 21-y = 12 / 19-x

18(19-x) = 12(21-y)

18(19-x) = 12(21- 12x/18)

x = 9         y = 6

 

I'll let you finish up your homework. smiley

 Dec 30, 2021
 #5
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+1

Thanks for answering Jugoslav.

 

However please don't state that a question is very simple because it sounds really insulting to the question asker.

In this case, I for one, do not think the question is as simple as you suggest.

 

Fuhsah, 

Jugoslav has given you some insight which may be enough for you.

If it is not enough then please ask for more help.

State what you have done to try and help yourself though.

Melody  Dec 30, 2021
 #6
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+1

I didn't mean to offend anyone. smiley

Guest Dec 30, 2021
 #7
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Yes I know. :)

Melody  Dec 30, 2021

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