+0  
 
0
53
1
avatar

The variable \(x\) varies directly as the square of \(y\), and \(y\) varies directly as the cube of \(z\). If \(x\) equals \(-16\) when \(z\) equals 2, what is the value of \(x\) when \(z\) equals \(\frac{1}{2}\)?

 Mar 23, 2020
 #1
avatar+23646 
+1

x = ky^2         y = k/z^3      combined      x = k /z^6      

 

-16 = k/ 2^3

k = -128    

 

x = -128 / z^6

x = -128 / (1/2)^3   = -1024

 Mar 24, 2020

28 Online Users

avatar
avatar