The volume of a box is 2208 cm3 The surface area is 480 cm2. What is the height of the box in centimeters?
Hi Chris,
I have looked through all of your working and it all looks good to me. (๑‵●‿●‵๑)
It is good that you went to all tihs effort.
I would just have said
With three unknowns you need three equations. Since there are only two equations you cannot find a single numerical answer. In this case you have found the answer - the answer does not exist - kind of funny don't you think?
There is no answer to this......here's why....
The surface area is given by
Sa = 480 = 2(lw + wh + lh)
240 = w( l + h) + lh
w = [240 - lh] / (l + h)
And the volume is given by
V = 2208 = lwh
2208/ [lh] = w
And setting the "w's" equal, we have
2208/[lh] = [240- lh] / (l + h) ..... cross-multiply
2208(l + h) = [240 - lh] lh
2208(l + h) = 240lh - (lh)^2 set to 0
(lh)^2 + 2208(l + h) - 240lh = 0
Now.....letting x = l and h = y.....look at the graph of
(xy)^2 + 2208(x + y) - 240xy = 0
https://www.desmos.com/calculator/eocxww2vmh
Notice that l and h both have to be greater than 0 because they are both lengths. Thus, x and y have to be greater than 0.
But notice.......if x and y were greater than 0, at least part of the graph would have to exist in the first quadrant....but it doesn't
Thus, there are no solutions......
P.S. .....would another mathematician check my logic here???......I believe this is correct, but I'm not sure.....!!!!
Hi Chris,
I have looked through all of your working and it all looks good to me. (๑‵●‿●‵๑)
It is good that you went to all tihs effort.
I would just have said
With three unknowns you need three equations. Since there are only two equations you cannot find a single numerical answer. In this case you have found the answer - the answer does not exist - kind of funny don't you think?