the x intercept of f(x)=log5 x is 1 whats the x-intercept of y=4f(3-x)+2 ?

y = 4log₅(3-x) + 2   .........set y =0

0 = 4log₅(3-x) + 2   .........subtract 2 from both sides

-2 = 4log₅(3-x)       ..........divide by  4

-1/2 = log₅(3-x)        ....in exponential form, we have

5 ^-1/2 = 3-x               .....or........

1/√5 = 3 -x              .......add x to both sides, subtract 1/√5 from both sides

x = 3 - 1/√5  =  [3√5 - 1]/√5 

So we have.......  ( [3√5 - 1]/√5 , 0 ) 

Thank you !