There are 5 shower rooms in a club house. the probability of any of the shower rooms being empty at 5:00 pm on a particular day is 0.4 Let X be the number of

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There are 5 shower rooms in a club house. the probability of any of the shower rooms being empty at 5:00 pm on a particular day is 0.4 Let X be the number of

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There are 5 shower rooms in a club house. the probability of any of the shower rooms being empty at 5:00 pm on a particular day is 0.4 Let X be the number of empty shower room on 5:00 pm, construct a probability distribution for the situation above

Guest Aug 3, 2015

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I am not really sure about the notation that is needed.

but

P(N rooms empty) = $^5C_N * 0.4^N * 0.6^{5-N}$ where $0\le N\le5\;\;\;and\;\;\;N\in Z$

Melody Aug 3, 2015

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Melody · Answer 1 · 2015-08-03T10:14:30

I am not really sure about the notation that is needed.

but

P(N rooms empty) = $^5C_N * 0.4^N * 0.6^{5-N}$ where $0\le N\le5\;\;\;and\;\;\;N\in Z$

There are 5 shower rooms in a club house. the probability of any of the shower rooms being empty at 5:00 pm on a particular day is 0.4 Let X be the number of

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