There are three lead bricks on a table, and you have a strangely designed scale that only functions properly when it has two bricks on it. So you put two of the bricks on and they weigh 24 pounds. Another set of two bricks weighs 26 pounds. The final set of two bricks weighs 30 pounds. How much does each brick weigh?
(Submit one weight in each answer field below. The order of your responses does not matter.)
Let the weight of the first brick = x, the second, y, and the third, z
And we have this system of equations:
x + y = 24 → y = 24 - x (1)
x + z = 26 → z = 26 - x (2)
y + z = 30 (3)
Substituting (1) and (2) into (3), we have
24 - x + 26 - x = 30 simplify
50 - 2x = 30
2x = 20 → x = 10 lbs and y = 24 - 10 = 14 lbs and z = 26 - 10 = 16 lbs
Let the weight of the first brick = x, the second, y, and the third, z
And we have this system of equations:
x + y = 24 → y = 24 - x (1)
x + z = 26 → z = 26 - x (2)
y + z = 30 (3)
Substituting (1) and (2) into (3), we have
24 - x + 26 - x = 30 simplify
50 - 2x = 30
2x = 20 → x = 10 lbs and y = 24 - 10 = 14 lbs and z = 26 - 10 = 16 lbs