Find the solutions of the equation x^2+36=0

There are no solutions over the real numbers.

Over the complex numbers the two solutions are

x = +/- 6i

where i is the square root of -1

x^2 + 36 = 0 subtract 36 from both sides

x^2 = -36 take both roots

x = ±√ - 36 = ±√ [ (-1)(36) ] = ± i * 6 = ± 6i

[ Remember that √ (-1) = i ]

Thanks CPhill and Rom