Find the solutions of the equation x^2+36=0
There are no solutions over the real numbers.
Over the complex numbers the two solutions are
x = +/- 6i
where i is the square root of -1
x^2 + 36 = 0 subtract 36 from both sides
x^2 = -36 take both roots
x = ±√ - 36 = ±√ [ (-1)(36) ] = ± i * 6 = ± 6i
[ Remember that √ (-1) = i ]
Thanks CPhill and Rom