+0  
 
0
1104
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avatar+308 

{nl} surpriseNEVERsurprise

 

a^x + b^y = c^z

Where A, B, C, x, y and z are positive integers and x, y and z are all greater than 2, then A, B and C must have a common prime factor. The challenge is to either solve that conjecture or come up with a counter-example.

 

Did I break your mind!?

 

Yes, I know I did.

 Jan 12, 2017
edited by Obscure  Jan 12, 2017
 #1
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No you didn't the answer is zero

 Jan 12, 2017
 #3
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It is sad you posted it twice. Its not 0 btw. XD You have to have shown work.

Obscure  Jan 12, 2017
 #2
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No you didn't the answer is zero

 Jan 12, 2017
 #4
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Lol

 Jan 12, 2017
edited by Guest  Jan 12, 2017

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