+0  
 
+1
46
3
avatar+311 

If the sum of 7 consecutive integers is 63, the sum of the largest and the smallest of the 7 integers is...

 

Answer Choices

A.18

B.24

C.42

D.64

 Jan 23, 2019
 #1
avatar+16286 
+3

x = first integer

x+1 = second    x+2 = next etc

 

x  +  x+1  +  x+2  +  x+3  +  x+4  +  x+5   +  x+6 = 63     gather all of the 'like' terms

7x  + 21=63     subtract 21 from both sides of the equation

7x = 42          divide thru by 7

x = 6 = smallest

x+6 = larges= 6+ 6= 12         6+ 12 = 18

 Jan 23, 2019
 #2
avatar+3830 
+2

We have: \(x-3, x-2, x-1, x, x+1, x+2, x+3\) . Adding all of these together, we get \(7x=63, x=9\) . The smallest number is \(6 \) and the largest number is \(12.\) Thus, the answer is \(6+12=\boxed{18}.\) (A).

 Jan 23, 2019
 #3
avatar+311 
0

Thanks EP and tertre!

 Jan 23, 2019

13 Online Users

avatar
avatar
avatar

New Privacy Policy

We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive information about your use of our website.
For more information: our cookie policy and privacy policy.