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If the sum of 7 consecutive integers is 63, the sum of the largest and the smallest of the 7 integers is...

 

Answer Choices

A.18

B.24

C.42

D.64

 Jan 23, 2019
 #1
avatar+18274 
+2

x = first integer

x+1 = second    x+2 = next etc

 

x  +  x+1  +  x+2  +  x+3  +  x+4  +  x+5   +  x+6 = 63     gather all of the 'like' terms

7x  + 21=63     subtract 21 from both sides of the equation

7x = 42          divide thru by 7

x = 6 = smallest

x+6 = larges= 6+ 6= 12         6+ 12 = 18

 Jan 23, 2019
 #2
avatar+4247 
+2

We have: \(x-3, x-2, x-1, x, x+1, x+2, x+3\) . Adding all of these together, we get \(7x=63, x=9\) . The smallest number is \(6 \) and the largest number is \(12.\) Thus, the answer is \(6+12=\boxed{18}.\) (A).

 Jan 23, 2019
 #3
avatar+404 
0

Thanks EP and tertre!

 Jan 23, 2019

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