If the sum of 7 consecutive integers is 63, the sum of the largest and the smallest of the 7 integers is...

Answer Choices

A.18

B.24

C.42

D.64

APatel Jan 23, 2019

#1**+2 **

x = first integer

x+1 = second x+2 = next etc

x + x+1 + x+2 + x+3 + x+4 + x+5 + x+6 = 63 gather all of the 'like' terms

7x + 21=63 subtract 21 from both sides of the equation

7x = 42 divide thru by 7

x = 6 = smallest

x+6 = larges= 6+ 6= 12 6+ 12 = 18

ElectricPavlov Jan 23, 2019