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This is the original equation sqrt of (11x+3) -2x = 0

I want to know if the extraneous sollution is -1/4 or 3. 

 

or if i did it totally wrong and it's neither -1/4 or 3.... '_'

 

-lrj

 Jan 28, 2016
edited by Guest  Jan 28, 2016
edited by Guest  Jan 28, 2016
edited by Guest  Jan 28, 2016
edited by Guest  Jan 28, 2016
edited by Guest  Jan 28, 2016

Best Answer 

 #1
avatar+129852 
+10

sqrt(11x + 3) - 2x = 0      add 2x to both sides

 

sqrt(11x + 3)  = 2x          square both sides

 

11x + 3  = 4x^2      rearrange

 

4x^2 - 11x - 3  = 0          factor

 

(4x  + 1) (x - 3)  = 0    setting both factors to 0, we have the possible solutions that x = -1/4  or x = 3

 

Checking these in the original equation, -1/4 is an extraneous solution, but 3 is a good solution

 

 

 

cool cool cool

 Jan 28, 2016
 #1
avatar+129852 
+10
Best Answer

sqrt(11x + 3) - 2x = 0      add 2x to both sides

 

sqrt(11x + 3)  = 2x          square both sides

 

11x + 3  = 4x^2      rearrange

 

4x^2 - 11x - 3  = 0          factor

 

(4x  + 1) (x - 3)  = 0    setting both factors to 0, we have the possible solutions that x = -1/4  or x = 3

 

Checking these in the original equation, -1/4 is an extraneous solution, but 3 is a good solution

 

 

 

cool cool cool

CPhill Jan 28, 2016

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