+99 This is the original equation sqrt of (11x+3) -2x = 0
I want to know if the extraneous sollution is -1/4 or 3.
or if i did it totally wrong and it's neither -1/4 or 3.... '_'
-lrj
+129899 sqrt(11x + 3) - 2x = 0 add 2x to both sides
sqrt(11x + 3) = 2x square both sides
11x + 3 = 4x^2 rearrange
4x^2 - 11x - 3 = 0 factor
(4x + 1) (x - 3) = 0 setting both factors to 0, we have the possible solutions that x = -1/4 or x = 3
Checking these in the original equation, -1/4 is an extraneous solution, but 3 is a good solution
+129899 sqrt(11x + 3) - 2x = 0 add 2x to both sides
sqrt(11x + 3) = 2x square both sides
11x + 3 = 4x^2 rearrange
4x^2 - 11x - 3 = 0 factor
(4x + 1) (x - 3) = 0 setting both factors to 0, we have the possible solutions that x = -1/4 or x = 3
Checking these in the original equation, -1/4 is an extraneous solution, but 3 is a good solution
