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If I choose four cards from a standard 52-card deck, with replacement, what is the probability that I will end up with one card from each suit?




plz help because i am really stumped on this one :( 


For the first draw.....we can get anything


For the second draw...we have a 3/4 chance of getting a different suite from the one on the first draw


For the third draw, we we have a (2/4) chance of getting a suite different from the first two


Finally.....on the last draw....we have a (1/4) chance of getting a different suite from the first three


So....the probability is


(1) (3/4) (2/4) (1/4)   =    6 / 64   =   3 / 32



cool cool cool

 Jun 6, 2019

Thanks so much CPhill..


I couldn't solve that one at all...




OK.....glad to help.....!!!


cool cool cool

CPhill  Jun 6, 2019

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