If I choose four cards from a standard 52-card deck, with replacement, what is the probability that I will end up with one card from each suit?
plz help because i am really stumped on this one :(
For the first draw.....we can get anything
For the second draw...we have a 3/4 chance of getting a different suite from the one on the first draw
For the third draw, we we have a (2/4) chance of getting a suite different from the first two
Finally.....on the last draw....we have a (1/4) chance of getting a different suite from the first three
So....the probability is
(1) (3/4) (2/4) (1/4) = 6 / 64 = 3 / 32