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If I choose four cards from a standard 52-card deck, with replacement, what is the probability that I will end up with one card from each suit?

 

 

 

plz help because i am really stumped on this one :( 

 #1
avatar+106533 
+1

For the first draw.....we can get anything

 

For the second draw...we have a 3/4 chance of getting a different suite from the one on the first draw

 

For the third draw, we we have a (2/4) chance of getting a suite different from the first two

 

Finally.....on the last draw....we have a (1/4) chance of getting a different suite from the first three

 

So....the probability is

 

(1) (3/4) (2/4) (1/4)   =    6 / 64   =   3 / 32

 

 

cool cool cool

 Jun 6, 2019
 #2
avatar+39 
+2

Thanks so much CPhill..

 

I couldn't solve that one at all...

 

😏😏

 #3
avatar+106533 
+1

OK.....glad to help.....!!!

 

cool cool cool

CPhill  Jun 6, 2019

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