The greatest common divisor of two integers is \((x+2)\) and their least common multiple is , where \(x(x+2)\) is a positive integer. If one of the integers is 24, what is the smallest possible value of the other one?
solve gcd(24, n) = x + 2 lcm(24, n) = x (x + 2) for n
n = 6 and x =4, so that:
GCD(24, 6) =4+2 =6
LCM(24,6) =4(4+2) =24
+51 
