Let $x$ and $y$ be real numbers such that $2(x^2 + y^2) = x + y.$ Find the maximum value of $x - y.$
my go at it:
First I expanded so I got 2x^2+2y^2=x+y, then I subtracted x and y on both sides resulting 2x^2-x+2y^2-y=0
Second I tried to make two factorable parts with x and y, so I made 2x^2-x+1/8+2y^2-y+1/8=1/8+1/8, resulting in
2(x-1/4)^2+2(y-1/4)^2, to make y as small as possible, since this is a square 0 is smallest so y=1/4,
next we find that 2(x-1/4)^2+0=2/8=1/4, square root both sides makes 2(x-1/4)=sqrt(1/4)=1/2
after expanding we get 2x-1/2=1/2, adding 1/2 to both sides we get 2x=1 so x=1/2. Since y=1/4, 1/2-1/4=1/4. However $1/4$ is incorrect pls help.
Omg Cphill is answering my question again!!!