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In a circuit, consisting of a 1kΩ resistor connected in series with 50 mH coil, a 10V rms, 10 kHz signal is applied. Find the impedance Z

Guest May 30, 2017
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 #1
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For a series circuit, the impedance equals the resistance plus the reactive inductance.

 

\(\text {Inductive Reactance (ohms)} = 2\Pi FL \Tiny \text { Where F is frequency in Hertz (Hz) & L is inductance in (Henrys)}\\ 2\Pi (10 kHz) \times (50mH) = 3.142k \varOmega \\ {3142 \varOmega + 1000\varOmega = 4142 \; \varOmega \; or \; 4.142K\varOmega } \)

Guest May 30, 2017
 #2
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You started off correctly, Guest, but series impedances don't add algebraically, they add according to Pythagoras.

 

 

So impedance Z = [(X)² + R² ]½

 

 

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Badinage  Jun 1, 2017
edited by Guest  Jun 1, 2017
edited by Badinage  Jun 1, 2017

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