We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive pseudonymised information about your use of our website. cookie policy and privacy policy.
 
+0  
 
0
125
1
avatar


Transpose the formula for ‘A’ and find the value of A when
k1 = k2 = 0.2

k3 = 0.5 

x1 = 40 x 10-3

x2 = 125 x 10-3

x3 = 60 x 10-3

Rt = 500

 Mar 8, 2019
 #1
avatar+22884 
+2

Transpose the formula for ‘A’ and find the value of A when
k1 = k2 = 0.2

k3 = 0.5 

x1 = 40 x 10-3

x2 = 125 x 10-3

x3 = 60 x 10-3

Rt = 500

\(\begin{array}{|rcll|} \hline R_T &=& \dfrac{x_1}{k_1A} + \dfrac{x_2}{k_2A} + \dfrac{x_3}{k_3A} \\\\ &=& \dfrac{1}{A}\left(\dfrac{x_1}{k_1 } + \dfrac{x_2}{k_2 } + \dfrac{x_3}{k_3 }\right)\\ \\ \mathbf{A} & \mathbf{=} & \mathbf{\dfrac{1}{R_T}\left(\dfrac{x_1}{k_1} + \dfrac{x_2}{k_2} + \dfrac{x_3}{k_3}\right)} \\\\ &=& \dfrac{1}{500}\cdot\left(\dfrac{40 \cdot 10^{-3}}{0.2} + \dfrac{125 \cdot 10^{-3}}{0.2} + \dfrac{60 \cdot 10^{-3}}{0.5}\right) \\\\ &=& \dfrac{10^{-3}}{500}\cdot\left(\dfrac{40}{0.2} + \dfrac{125}{0.2} + \dfrac{60}{0.5}\right) \\\\ &=& \dfrac{10^{-3}}{500}\cdot\left(\dfrac{40\cdot 10}{ 2} + \dfrac{125\cdot 10}{2} + \dfrac{60\cdot 10}{5}\right) \\\\ &=& \dfrac{10^{-3}\cdot 10}{500}\cdot\left(\dfrac{40}{ 2} + \dfrac{125}{2} + \dfrac{60}{5}\right) \\\\ &=& \dfrac{10^{-3}\cdot 10}{5\cdot 10^2}\cdot\left(\dfrac{40}{ 2} + \dfrac{125}{2} + \dfrac{60}{5}\right) \\\\ &=& \dfrac{10^{-3}}{50} \cdot (20 + 62.5 + 12 ) \\\\ &=& \dfrac{94.5\cdot 10^{-3}}{50} \\\\ \mathbf{A} & \mathbf{=} & \mathbf{1.89\cdot 10^{-3}} \\ \hline \end{array}\)

 

laugh

 Mar 8, 2019

26 Online Users

avatar
avatar