As shown in the diagram, PQ is the median of trapezoid ABCD where AB = 25 inches and CD = 30 inches. Find XY in inches.
Triangle AOB is similar to triangle COD
Then since base CD = 6/5 of base AB, then the height of COD = (6/5) that of triangle AOB
Then there 11 equal parts to the height of the trapezoid ...... and 11/2 = 5.5 equal parts on each side of the midline
And since the height of AOB contains 5 of these......then the height of triangle YOX must = .5 of these
And triangles YOX and COD are similar
base of YOX / base of COD = .5 / 6 = 1/12
So XY =(1/12) CD = 30 / 12 = 5/2 in = 2.5 in