\(Triangle $ABC$ has a right angle at $B$. Legs $\overline{AB}$ and $\overline{CB}$ are extended past point $B$ to points $D$ and $E$, respectively, such that $\angle EAC = \angle ACD = 90^\circ$. Prove that $EB \cdot BD = AB \cdot BC$\)
I think she is saying that ABC has a right angle at B. Legs AB and CB are extended past point B to points D and E, respectively, such that <EAC=<ACD=90*. Prove that EB * BD = AB * BC.
I think she is saying that ABC has a right angle at B. Legs AB and CB are extended past point B to points D and E, respectively, such that <EAC=<ACD=90*. Prove that EB * BD = AB * BC.
+1833 
