Triangle ABC, inscribed in a circle, has AB = 15 and BC = 35. A tangent to the circle is drawn at B, and a line through A parallel to this tangent intersects BC at D. Find DC.
Triangle ABC, inscribed in a circle, has AB = 15 and BC = 35. A tangent to the circle is drawn at B, and a line through A parallel to this tangent intersects BC at D. Find DC.
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Hello, Guest! I think that BC should be 25 instead of 35. If BC = 25 then DC = 16
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Let angle ABC = 90º
Angle BAD = arctan(15 / 35)
BD = tan∠BAD * AB = 6.428571429
DC = BC - BD = 28.57142857