What is the radius of the circle inscribed in triangle ABC if AB = 10, AC = 17, BC = 21? Express your answer as a decimal to the nearest tenth.
We can find the area of this triangle using Heron's Formula
s = [ 10 + 17 + 21 ] / 2 = 48 / 2 = 24
The area = √ [ s (s - 10) (s - 17) (s - 21) ] =
√ [ 24 (14) (7) (3) ] =
√7056 = 84 units^2
The area = 1/2 [ sum of triangle's sides ] * altitude of each triangle
But....the altitude of each triangle = the radius of the incircle
So...we have
84 = (1/2) (48) * radius of incircle
84 = 24 * radius of incircle
84 / 24 = rasius of incircle = 3.5 units
EDIT TO CORRECT AN ERROR !!!!