Let triangle XOY be a right-angled triangle with XOY being 90 degrees. Let M and N be the midpoints of legs OX and OY respectively. Given that XN=24 and YM=31, find XY (aka the hypotenuse).
Let triangle XOY be a right-angled triangle with XOY being 90 degrees. Let M and N be the midpoints of legs OX and OY respectively. Given that XN=24 and YM=31, find XY (aka the hypotenuse).
OX => a OY => b
242 = (b/2)2 + a2
576 - (b/2)2 = a2
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(a/2)2 = 312 - b2
a2 / 4 = 961 + b2
a2 = 3844 - 4b2 a2 = 358.13333333
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576 - b2 / 4 = 3844 - 4b2
b2 = 13072 / 15 b2 = 871.4666667
XY = sqrt( a2 + b2 ) = 35.0656527