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# triangle problem

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An isosceles triangle has a height of 12 cm and an area of 28 square cm. How many cm's are in the perimeter of the triangle? Express your answer in simplest radical form.

Feb 22, 2021

#1
+944
+1

$$A = \frac{bh}{2} = \frac{12b}{2} = 28 \quad \rightarrow \quad b = \frac{14}{3}$$

$$P = b + 2\sqrt{b^2 + h^2} = \frac{14}{3} + 2\sqrt{(\frac{14}{3})^2 + 12^2}$$

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Feb 22, 2021

#1
+944
+1
$$A = \frac{bh}{2} = \frac{12b}{2} = 28 \quad \rightarrow \quad b = \frac{14}{3}$$
$$P = b + 2\sqrt{b^2 + h^2} = \frac{14}{3} + 2\sqrt{(\frac{14}{3})^2 + 12^2}$$