triangle question

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In triangle PQR, PQ=13 , QR=14 , and PR=16 . Let M be the midpoint of QR . Find PM.

Guest Mar 30, 2022

Elijah · Answer 1 · 2022-03-30T04:35:35

What kind of triangle is it? Can we see a diagram?

Guest · Answer 2 · 2022-03-31T01:21:33

Cosine rule in PQR:

$\displaystyle \cos Q = \frac{13^{2}+14^{2}-16^{2}}{2.13.14}\; .$

Cosine rule in PQM:

$\displaystyle PM^{2}=7^{2}+13^{2}-2.7.13.\cos Q .$