In triangle $ABC,$ $\angle A = p + 2q$ degrees, $\angle B = 6p - 8q$ degrees, and $\angle C = 17p + 2q$ degrees. Find $p$ (in degrees).
(p + 2q) + (6p - 8q) + (17p + 2q)=180, solve for p
From the above eqation we obtain:
p = (q + 45) / 6. Try q=1, 2, 3..........etc.
The smallest q that balances the equation =3
p =(3 + 45) / 6 ==8 - the smallest value of p that balances the equation.
