+1768 An equilateral triangle has sides $8$ units long. An equilateral triangle with sides $2$ units long is cut off at the top, leaving an isosceles trapezoid. What is the ratio of the area of the smaller triangle to the area of the trapezoid? Express your answer as a common fraction.
+129850 The height of the trapezoid is 3 times the height of the equilateral triangle
Area of equilateral triangle = (1/2)base * height = (1/2) (2) (H) = H
Bases of trapezoid = 2 , 8......height = 3H
Area of trapezoid= (1/2) (3H)( 2 + 8) = 15H
Ratio of areas = H / ( 15H) = 1 / 15
