+257 Let triangle ABC be a right triangle such that B is at the right angle. A circle with a diameter of BC meets side AC at D. If the area of triangle ABC is 150 and AC=25 then what is BD?
(no visual given)
+128475 
OK....I think I have it.....letting BC = 15 and and BA = 20
Then AC = 25
And the product of the legs BC * BA / 2 = the area = 150
The circle is centered at (0, 7.5) and has a radius of 7.5
Notice in the diagram....angle ADB = 90°.....so BD is an altitude of triangle ABC
So...letting AC be a base...we have that
Area of ABC = (1/2) base * altitude
150 = (1/2)AC * ( BD)
150 = (1/2)AC * BD
150 = (1/2)(25) (BD)
300 = 25 (BD)
300 /25 = BD = 12
