We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive pseudonymised information about your use of our website. cookie policy and privacy policy.
 
+0  
 
0
146
5
avatar+256 

Let triangle ABC be a right triangle such that B is at the right angle. A circle with a diameter of BC meets side AC at D.  If the area of triangle ABC  is 150 and AC=25 then what is BD?

(no visual given)

 Apr 10, 2019
 #1
avatar+104069 
+1

Kinda' hard to answer without a pic, SS.....

 

 

cool cool cool

 Apr 10, 2019
 #2
avatar+256 
+1

this was all that was given and that's what I thought as well but I figured anyone on here had more experience and might be able to figure it out differently.

SydSu22  Apr 10, 2019
 #3
avatar+104069 
+1

 

 

OK....I think I have it.....letting BC = 15  and  and BA    = 20

Then AC  = 25

And the product of the legs BC * BA  / 2  =  the area  = 150

 

The circle is centered at  (0, 7.5)  and has a radius of 7.5

 

Notice in the diagram....angle ADB  = 90°.....so  BD  is an altitude of triangle ABC

So...letting AC  be a base...we have that

 

Area of ABC  = (1/2) base * altitude

 

150 = (1/2)AC * ( BD)

 

150  = (1/2)AC * BD

 

150  = (1/2)(25) (BD)

 

300 = 25 (BD)

 

300 /25  = BD  =   12

 

 

cool cool cool

 Apr 10, 2019
 #4
avatar+256 
+1

OMGosh that is amazing and this is one of the reasons I come here when I need help!

SydSu22  Apr 10, 2019
 #5
avatar+104069 
+1

Well...I'm not great at Geometry.....but....I can do a little   !!!!

 

 

cool coolcool

CPhill  Apr 10, 2019

14 Online Users