A circle is circumscribed about an equilateral triangle with side lengths of 9 units each. What is the area of the circle, in square units? Express your answer in terms of pi.
Equilateral triangle radius of circumcircle = \(\frac{s}{\sqrt{3}}\)
Which means \(r = 3\sqrt{3}\)
Area of a circle is Pi*r^2
Substitute to get \(\Pi ({3\sqrt{3})}^2\)
Which is equal to \(27\Pi\)
The area of the circumcircle is \(27\Pi -units^2\)