Using the sum of angles of a triangle formula on the leftmost triangle, we find that $36+63+x=180$. Solving gives $\boxed{x=81}$
Knowing now that $x=81$, we see that since $x$ and $z$ lie on the same line, $x+z=180$. We already know what $x$ is, so we have $81+z=180$. Solving gives $\boxed{z=99}$
Now using the sum of angles of a triangle formula again on the rightmost triangle, we find that $13+z+y=180$. But we already know what $z$ is! $z=99$! So we have $13+99+y=180$. Solving gives $\boxed{y=68}$.
FINAL ANSWERS: $\boxed{x=81, y=68, z=99}$
Using the sum of angles of a triangle formula on the leftmost triangle, we find that $36+63+x=180$. Solving gives $\boxed{x=81}$
Knowing now that $x=81$, we see that since $x$ and $z$ lie on the same line, $x+z=180$. We already know what $x$ is, so we have $81+z=180$. Solving gives $\boxed{z=99}$
Now using the sum of angles of a triangle formula again on the rightmost triangle, we find that $13+z+y=180$. But we already know what $z$ is! $z=99$! So we have $13+99+y=180$. Solving gives $\boxed{y=68}$.
FINAL ANSWERS: $\boxed{x=81, y=68, z=99}$