A four-digit number (not beginning with 0) can be represented by ABCD. There is one number such that ABCD=A^B*C^D, where A^B means A raised to the B power. Can you find it?
Wait, so A^B * C^D right, not A^{(B*C)^D}?
Also, there are whole lot of users on right now...
No! I just wrote the code in about a minute. Here it is if you want to see it.
a=1; b=1;c=1;d=1;p=1;m=a*1000+b*100+c*10+d;n=(a^b)*(c^d);if(m==n, goto loop, goto next);loop:printm;next:a++;if(a<10, goto5, 0);a=1;b++;if(b<10, goto5, 0);a=1;b=1;c++;if(c<10, goto5,0);a=1;b=1;c=1;d++;if(d<10, goto5, discard=0;
dang! You can solve riddles with computer code? Who knows what the future might look like 10 years from now.
Robots programming themselves? its time for terminator...