Hi friends,
I hopefully have only 2 more questions for today. Both these questions come from the same problem. Please explain to me..please...
The 2nd step in the sum goes like this:
\({Sin135Cosx - Cos135Sinx} \over{Sinx}\)
becomes:
\({Sin45Cosx + Cos45Sinx \over Sinx}\)
How can this be?...sorry if I'm wasting someone's time with this one......I tried to make the font a little bigger...unsuccessful.
Seems like you need to study up on the unit circle.
Here is a play page.
Its great if you already understand what you are looking at but maybe not so great if you don't.
https://www.mathsisfun.com/geometry/unit-circle.html
This video looks really good. I have only watch about half but she sweemed to be explaining it really well.
summarizing.
If an angle is drawn on the unit circle as shown in the video, the hypotenuse of any triangle will be 1.
So
cos of the angle is the x value on the circumference of the unit circle So cos will be positive in the 1st and 4th quadrants
sin of the angle is the y value on the circumference of the unit circle So sin will be positive in the 1st and 2nd quadrants
tan of the angle is the y value divided by the x value on the circumference of the unit circle So tan will be positive in the 1st and 3rd quadrants
A sentance to help you with this is ALL Stations To Central
All trig values are positive for angles less than 90 degrees, that is angles in the 1st quadrant
Sin (but not cos or tan) will be positive for all angles in the 2nd quadrant, that is angles between 90 and 180 degrees
Tan is positive in the 3rd quadrant
Cos is positive in the 4th quadrant.
so
sin135 = +sin (180-135) Note: it is in the secend quadrant fo it is positive
sin 135 = sin 45
Maybe you can try the rest yourself.
my my my ...goodness!!!..off course!
gosh, you know what Melody...I have looked at for example Sin 140, as Sin 140 DEG, and therefore could not understand how on earth 135 DEGREES could be the same as 45 DEGREES
but yes, I see my error. Getting the actual values of the different Sin values, equate to the same answer....ALL RIGHTIE!!!...
Just a last thing...The different quads where the trig functions are either positive or negative, I fully understand, I use the phrase CAST, starting with quad 4...C=Cos, A=All, S=Sin and T=Tan...(obviously..)
Thank you Melody for going through the trouble of finding those urls, I have not watched them, since I understand all of this, I just made a stupid error for mistaking the value for an angle...
I'm sending a BIG BUNCH of flowers!!