Can anyone help with this trig function problem? I'm not getting it.

g is a trigonometric function of the form g(x)=a*cos(bx+c)+d Below is the graph of g(x). the function has a maximum point at (, -2) and a minimum point at (, -14). Find a formula for g(x), . Give an exact expression.

Guest Jul 17, 2020

#1**+1 **

The usual amplitude of a sin or cos wave is 1 and they go from +1 to -1 ( a height of 2 amplitude = height/2)

this wave goes from -14 to -2 a height of 12 height/2 = 6 for amplitude

so 'a' in your equation is 6 it multiplies the wave by 6

6 cos (bx+c ) + d

'd' shifts the wave up or down.... the usual sin or cos wave has a midline at y = 0

ths one has a midline at y = -8 shifted down 8

6 cos (bx+c) - 8

'b' stretches or compresses the wave

usual period for sin or cos wave is 2pi

this one has 1/2 of a period from 3/4 pi to 2 pi full period is 2* (2pi- 3/4 pi ) = 10/4 pi

it is stretched out by 'b' 2pi / ( 10/4 pi) = 8/10 = 4/5 =b

6 cos (4/5 x +c) -8

'c' shifts the wave left or right ...

this cos wave is shited RIGHT 3/4 pi (the high point of cos wave is usually at 0 this one is at 3/4 pi)

SUBTRACTING SHIFTS RIGHT

BUT wecompressed the wave with 'b' so 'c' will need to be compressed too

3/4 pi * 4/5 = 3/5 pi

6 cos (4/5 x -3/5 pi ) - 8

ElectricPavlov Jul 17, 2020