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Graph any acute radian angle \(\theta\). Then, use that picture to find where each requested angle would be located. Remember, \(\pi\)radians is equal to half a revolution, or 180o.

AdamTaurus  Jan 24, 2018
 #1
avatar+92816 
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Adam, let me know if you don't know how to graph these....I'm using  pi/6  as θ

 

a)  -θ  =  -pi/6

 

b)  pi + θ   =  pi  + pi /6  =   6pi / 6  + pi/6   =  7pi/6

 

c) pi - θ   =  pi - pi/6  =  6pi/6  - pi/6  = 5pi/6

 

 

cool cool cool

CPhill  Jan 24, 2018

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