Graph any acute radian angle \(\theta\). Then, use that picture to find where each requested angle would be located. Remember, \(\pi\)radians is equal to half a revolution, or 180o.
Adam, let me know if you don't know how to graph these....I'm using pi/6 as θ
a) -θ = -pi/6
b) pi + θ = pi + pi /6 = 6pi / 6 + pi/6 = 7pi/6
c) pi - θ = pi - pi/6 = 6pi/6 - pi/6 = 5pi/6
+895 
